Yes, it seems so. I'm leaning towards the energy efficient quad-core.

I found a couple of interesting bits of information:

1) The equation

*P = CV^2f* from the

**Wikipedia SpeedStep article**. I think it roughly applies to all processors. I did some calculating for fun, and for the 910e, I got a capacitance of 16 (not sure of the unit), and for the 1055T (95W version) 16,7 (and, for the 125W version, 20,5 btw). I used the specified maximum frequency and operating voltage.

I even went to the lenght of calculating a theoretical TDP when underclocking for these and some other processors via the equation above (this is of course not correct, but just an excersise and a rough estimate to give some direction. You'll get a linear correlation).

2) While doing this I found some

**voltage ramps from tomshardware** -

**THIS was exactly what I was lookin for when posting this thread!)**. But, no tests for 910e (or similar) and no 1055T 95W TDP version there

.

But, then I calculated the C for some processors found on the article linked above, and roughly estimated the current when underclocking - and of course, compared the results

. My calculations are more optimistic than the real measurements (they don't take the voltage decrease into account), and even more so on lower frequencies. But at >2,0GHz the difference is only in the order of few watts. According to my calculations, it seems that the energy efficient 910e would be much cooler than the 95W 1055T at the same frequency (for example, 88,2W vs. 65W @ 2,6GHz).

I also calculated the C value for all Phenom II X6 processors. With this method, only one has a C value lower than 16 - this is the Phenom II X6 1065T 95W version (at 15,06), but it can't be found on sale anywhere. I guess it COULD run cooler at, say 2,6GHz than the 910e, but also might not, since the correlation is not linear - i.e. C is not constant but only roughly (another matter is, why it is not constant).

Of course, this is just speculation and I might be wrong. Real-world tests would be needed. And I don't think there are a lot of people around to do the power measurements required for this

And, of course every chip is an individual, even in this aspect

. If you're lucky, you might get one that runs at a lower voltage and lower current (even at load).

Any comments?

Cheers!